Two goods trains,each 500 ; m long,are runnin | vedclass

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Question

(B) When two trains move in opposite directions,their relative speed is the sum of their individual speeds.Relative speed $= 45 \; km/hr + 30 \; km/hr

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(B) When two trains move in opposite directions,their relative speed is the sum of their individual speeds.Relative speed $= 45 \; km/hr + 30 \; km/hr = 75 \; km/hr$.To convert the speed into $m/s$,multiply by $\frac{5}{18}$:Relative speed $= 75 	imes \frac{5}{18} = \frac{375}{18} = \frac{125}{6} \; m/s$.To pass the driver of the faster train,the slower train needs to cover a distance equal to its own length,which is $500 \; m$.Time taken $(t) = \frac{	ext{Distance}}{	ext{Relative speed}}$.$t = \frac{500}{\frac{125}{6}} = 500 	imes \frac{6}{125} = 4 	imes 6 = 24 \; seconds$.

Two goods trains,each $500 \; m$ long,are running in opposite directions on parallel tracks. Their speeds are $45 \; km/hr$ and $30 \; km/hr$ respectively. Find the time (in $seconds$) taken by the slower train to pass the driver of the faster one.

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