Two grams of hydrogen diffuse from a containe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Graham's Law of diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r \propto \f

Vedclass · Accepted Answer

$0.5$

Vedclass · Answer

(A) According to Graham's Law of diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r \propto \frac{1}{\sqrt{M}}$.Since the time $t$ is the same for both gases,the rate of diffusion is proportional to the mass $m$ diffused: $r = \frac{m}{t}$.Therefore,$\frac{m_{H_2}}{m_{O_2}} = \sqrt{\frac{M_{O_2}}{M_{H_2}}}$.Given $m_{H_2} = 2 \ g$,$M_{H_2} = 2 \ g/mol$,and $M_{O_2} = 32 \ g/mol$.Substituting the values: $\frac{2}{m_{O_2}} = \sqrt{\frac{32}{2}} = \sqrt{16} = 4$.Thus,$m_{O_2} = \frac{2}{4} = 0.5 \ g$.

Two grams of hydrogen diffuse from a container in $10 \ min$. How many grams of oxygen would diffuse through the same container in the same time under similar conditions?

Similar Questions

$A$ sample of air contains $N_2$ and $O_2$ saturated with water vapor,with a total pressure of $640 \ torr$. If the water vapor pressure is $40 \ torr$ and the molar ratio of $N_2$ to $O_2$ is $3 : 1$,what is the partial pressure of $N_2$ in the sample in $torr$?

Explain the effect of increasing the temperature of a liquid on the intermolecular forces operating between its particles. What will happen to the viscosity of a liquid if its temperature is increased?

Which of the following mixtures of gases does not obey Dalton's law of partial pressure?

Helium is added to the oxygen supply used by deep sea divers because

The densities of two gases are in the ratio of $1 : 16$. The ratio of their rates of diffusion is

Vedclass Test Series

Exam Paper Generator

Online Exam Module