Two homo-diatomic molecules X_2 and Y_2 have | vedclass

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(C) The bond order of a molecule is defined by the formula: $	ext{Bond Order} = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons a

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The difference between the total number of antibonding electrons and bonding electrons must be the same for both molecules.

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(C) The bond order of a molecule is defined by the formula: $	ext{Bond Order} = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.If two molecules have the same bond order,then $\frac{N_{b1} - N_{a1}}{2} = \frac{N_{b2} - N_{a2}}{2}$.This implies that $N_{b1} - N_{a1} = N_{b2} - N_{a2}$.Therefore,the difference between the number of bonding and antibonding electrons must be the same for both molecules.Option $(C)$ correctly states this relationship.

Two homo-diatomic molecules $X_2$ and $Y_2$ have the same bond order. Then,select the $CORRECT$ statement.

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