Two ideal electric dipoles A and B having dip | vedclass

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(B) The electric field due to dipole $A$ at point $C$ (on its axial line) is $E_{A} = \frac{2kp_{1}}{r^{3}}$ directed along the axis.The electric fiel

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$\frac{2}{3}$

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(B) The electric field due to dipole $A$ at point $C$ (on its axial line) is $E_{A} = \frac{2kp_{1}}{r^{3}}$ directed along the axis.The electric field due to dipole $B$ at point $C$ (on its equatorial line) is $E_{B} = \frac{kp_{2}}{r^{3}}$ directed perpendicular to the axis.The resultant electric field makes an angle of $37^{\circ}$ with the axis,so:$	an 37^{\circ} = \frac{E_{B}}{E_{A}}$Given $\sin 37^{\circ} = \frac{3}{5}$,we have $\cos 37^{\circ} = \frac{4}{5}$,so $	an 37^{\circ} = \frac{3}{4}$.Substituting the values:$\frac{3}{4} = \frac{\frac{kp_{2}}{r^{3}}}{\frac{2kp_{1}}{r^{3}}} = \frac{p_{2}}{2p_{1}}$Rearranging for the ratio $\frac{p_{1}}{p_{2}}$:$\frac{p_{1}}{p_{2}} = \frac{4}{2 	imes 3} = \frac{4}{6} = \frac{2}{3}$.

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