Two identical conducting spheres $A$ and $B$ carry equal charge. They are separated by a distance much larger than their diameter,and the force between them is $F$. $A$ third identical conducting sphere,$C$,is uncharged. Sphere $C$ is first touched to $A$,then to $B$,and then removed. As a result,the force between $A$ and $B$ would be equal to

  • A
    $\frac{3F}{4}$
  • B
    $\frac{F}{2}$
  • C
    $F$
  • D
    $\frac{3F}{8}$

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