(B) Let the initial capacitance of each capacitor be $C$. When one capacitor is filled with a dielectric of constant $K$,its new capacitance becomes $

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(B) Let the initial capacitance of each capacitor be $C$. When one capacitor is filled with a dielectric of constant $K$,its new capacitance becomes $C' = KC$.The two capacitors are connected in series to a battery of e.m.f. $V$.Let $C_1 = KC$ be the capacitance of the dielectric-filled capacitor and $C_2 = C$ be the capacitance of the air-filled capacitor.The potential difference across the air-filled capacitor $(C_2)$ in a series combination is given by the voltage divider rule:$V_2 = V \times \frac{C_1}{C_1 + C_2}$Substituting the values:$V_2 = V \times \frac{KC}{KC + C}$$V_2 = V \times \frac{KC}{C(K + 1)}$$V_2 = \frac{KV}{K + 1}$

Class 12 Physics Electric Potential and Capacitance Effect of Dielectric Inside Capacitor

Medium

Two identical parallel plate air capacitors are connected in series to a battery of e.m.f. $V$. If one of the capacitors is inserted in a liquid of dielectric constant $K$,then the potential difference across the other capacitor will become:

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A
$\frac{K}{V(K+1)}$
B
$\frac{KV}{K+1}$
C
$\frac{K+1}{KV}$
D
$\frac{K}{V(1-K)}$

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Class 12

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Electric Potential and Capacitance

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Effect of Dielectric Inside Capacitor

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Two identical parallel plate air capacitors are connected in series to a battery of e.m.f. $V$. If one of the capacitors is inserted in a liquid of dielectric constant $K$,then the potential difference across the other capacitor will become:

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