Two identical parallel plate capacitors of capacitance $C$ each are connected in series with a battery of emf $E$ as shown below. If one of the capacitors is now filled with a dielectric of dielectric constant $k$,then the amount of charge which will flow through the battery is (neglect internal resistance of the battery).

  • A
    $\frac{k+1}{2(k-1)} \cdot C E$
  • B
    $\frac{k-1}{2(k+1)} \cdot C E$
  • C
    $\frac{k-2}{k+2} \cdot C E$
  • D
    $\frac{k+2}{k-2} \cdot C E$

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