Two identical thin isosceles prisms of refrac | vedclass

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(C) The deviation produced by a thin prism is given by $\delta = (\mu - 1)A$.From the geometry of the system,the rays are incident at a distance $h$ f

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$\frac{h}{(\mu - 1)A}$

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(C) The deviation produced by a thin prism is given by $\delta = (\mu - 1)A$.From the geometry of the system,the rays are incident at a distance $h$ from the principal axis.After passing through the prism,the rays deviate by an angle $\delta$ towards the principal axis.In the right-angled triangle formed by the deviation,we have $	an \delta = \frac{h}{f}$,where $f$ is the distance of the convergence point from the prism.Since the prism is thin,$\delta$ is small,so $	an \delta \approx \delta$.Therefore,$\delta = \frac{h}{f} \Rightarrow f = \frac{h}{\delta}$.Substituting the expression for $\delta$,we get $f = \frac{h}{(\mu - 1)A}$.

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