Two insulated charged copper spheres A and B | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Distance between the spheres $A$ and $B$,$r = 0.5 \; m$.Initially,the charge on each sphere,$q = 6.5 	imes 10^{-7} \; C$.When sphere $A$ is touch

Vedclass · Accepted Answer

$5.7 	imes 10^{-3} \; N$.

Vedclass · Answer

(B) Distance between the spheres $A$ and $B$,$r = 0.5 \; m$.Initially,the charge on each sphere,$q = 6.5 	imes 10^{-7} \; C$.When sphere $A$ is touched with an uncharged sphere $C$,the charge $q$ is shared equally. Hence,the charge on each of the spheres $A$ and $C$ becomes $q_A = q/2$.When sphere $C$ (now with charge $q/2$) is brought in contact with sphere $B$ (with charge $q$),the total charge is shared equally between them. The new charge on each is $(q + q/2) / 2 = 3q/4$. So,$q_B = 3q/4$.The new force of repulsion between $A$ and $B$ is given by Coulomb's law:$F = \frac{1}{4 \pi \varepsilon_0} \cdot \frac{q_A q_B}{r^2} = (9 	imes 10^9) \cdot \frac{(q/2) \cdot (3q/4)}{r^2} = (9 	imes 10^9) \cdot \frac{3q^2}{8r^2}$.Substituting the values: $F = (9 	imes 10^9) \cdot \frac{3 	imes (6.5 	imes 10^{-7})^2}{8 	imes (0.5)^2} = 5.703 	imes 10^{-3} \; N$.

Similar Questions

$A$ charge $q_1$ exerts some force on a second charge $q_2$. If a third charge $q_3$ is brought near,the force of $q_1$ exerted on $q_2$:

What is the force between two small charged spheres having charges of $2 \times 10^{-7} C$ and $3 \times 10^{-7} C$ placed $30 cm$ apart in air?

The force between two point charges $A$ and $B$ is $F$. If $75\%$ of the charge of $A$ is transferred to $B$,then the new force between $A$ and $B$ is:

Why is the Coulombian force called a two-body force?

Equal charges $q$ are placed at the four corners $A, B, C, D$ of a square of side length $a$. The magnitude of the net electrostatic force on the charge at $B$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module