Two lamps,one rated $100 \, W$ at $220 \, V$ and the other $60 \, W$ at $220 \, V$,are connected in parallel to a $220 \, V$ supply. Find the current drawn from the supply line.
(D) The power $P$ and voltage $V$ are given for both lamps. The current $I$ drawn by each lamp can be calculated using the formula $P = VI$,or $I = P/V$.
For the first lamp,$I_1 = P_1 / V = 100 \, W / 220 \, V = 10/22 \, A = 5/11 \, A$.
For the second lamp,$I_2 = P_2 / V = 60 \, W / 220 \, V = 6/22 \, A = 3/11 \, A$.
Since the lamps are connected in parallel,the total current $I$ drawn from the supply is the sum of the individual currents:
$I = I_1 + I_2 = 5/11 \, A + 3/11 \, A = 8/11 \, A$.
$I \approx 0.727 \, A$.
For the first lamp,$I_1 = P_1 / V = 100 \, W / 220 \, V = 10/22 \, A = 5/11 \, A$.
For the second lamp,$I_2 = P_2 / V = 60 \, W / 220 \, V = 6/22 \, A = 3/11 \, A$.
Since the lamps are connected in parallel,the total current $I$ drawn from the supply is the sum of the individual currents:
$I = I_1 + I_2 = 5/11 \, A + 3/11 \, A = 8/11 \, A$.
$I \approx 0.727 \, A$.
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