Two light waves having the same wavelength la | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The optical path length of a wave traveling through a medium of refractive index $n$ and geometric path length $L$ is given by $OPL = n 	imes L$.

Vedclass · Accepted Answer

$\frac{2 \pi}{\lambda}(n_{1}L_{1} - n_{2}L_{2})$

Vedclass · Answer

(A) The optical path length of a wave traveling through a medium of refractive index $n$ and geometric path length $L$ is given by $OPL = n 	imes L$.The optical path length for the first wave is $OPL_{1} = n_{1}L_{1}$.The optical path length for the second wave is $OPL_{2} = n_{2}L_{2}$.The optical path difference between the two waves is $\Delta p = |OPL_{1} - OPL_{2}| = |n_{1}L_{1} - n_{2}L_{2}|$.The phase difference $\Delta \phi$ is related to the path difference $\Delta p$ by the formula $\Delta \phi = \frac{2 \pi}{\lambda} \Delta p$.Substituting the path difference,we get $\Delta \phi = \frac{2 \pi}{\lambda} (n_{1}L_{1} - n_{2}L_{2})$.

Similar Questions

The ratio of the amplitudes of two interfering waves is $3 : 4$. What is the ratio of their intensities?

An interference pattern is obtained with two coherent sources of intensity ratio $n:1$. The ratio $\frac{I_{\text{Max}}-I_{\text{Min}}}{I_{\text{Max}}+I_{\text{Min}}}$ will be maximum if

The phenomenon of interference is based on

Two light waves of intensities $I_0$ and $9I_0$ superpose at a point to produce a resultant intensity of $7I_0$. Calculate the phase difference between the light waves.

The ratio of the intensities of two waves is $25 : 1$. If interference occurs,then the ratio of the maximum and minimum intensity should be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module