Two masses m_1 and m_2 (m_1

Question

(A) The gravitational force $F$ acting on both masses is equal in magnitude and opposite in direction.According to Newton's second law,$F = ma$,which

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acceleration of $m_1$ is more than that of $m_2$

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(A) The gravitational force $F$ acting on both masses is equal in magnitude and opposite in direction.According to Newton's second law,$F = ma$,which implies $a = F/m$.Since the force $F$ is the same for both,the acceleration $a$ is inversely proportional to the mass $m$ $(a \propto 1/m)$.Given $m_1  a_2$. Thus,the acceleration of $m_1$ is greater than that of $m_2$.Since the gravitational force is an internal force for the system,there is no external force acting on the system.Therefore,the total energy of the system remains constant.

Two masses $m_1$ and $m_2$ $(m_1 < m_2)$ are released from rest from a finite distance. They start moving under their mutual gravitational attraction.

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