Two masses of 1 ,g and 4 ,g are moving with e | vedclass

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Question

(C) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by $P = \sqrt{2mE}$.Since the kinetic energies $E$ are equal

Vedclass · Accepted Answer

$1:2$

Vedclass · Answer

(C) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by $P = \sqrt{2mE}$.Since the kinetic energies $E$ are equal for both masses,we have $P \propto \sqrt{m}$.Therefore,the ratio of their linear momenta is $\frac{P_1}{P_2} = \sqrt{\frac{m_1}{m_2}}$.Substituting the given values $m_1 = 1 \,g$ and $m_2 = 4 \,g$,we get $\frac{P_1}{P_2} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.Thus,the ratio is $1:2$.

Two masses of $1 \,g$ and $4 \,g$ are moving with equal kinetic energies. The ratio of the magnitudes of their linear momenta is

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