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Question

(B) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energy $E$

Vedclass · Accepted Answer

$1:4$

Vedclass · Answer

(B) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energy $E$ is equal for both masses,we have $P \propto \sqrt{m}$.Therefore,the ratio of the linear momenta is $\frac{P_1}{P_2} = \sqrt{\frac{m_1}{m_2}}$.Given $m_1 = 1\,kg$ and $m_2 = 16\,kg$,we get $\frac{P_1}{P_2} = \sqrt{\frac{1}{16}} = \frac{1}{4}$.Thus,the ratio is $1:4$.

Two masses of $1\,kg$ and $16\,kg$ are moving with equal kinetic energy. The ratio of the magnitude of their linear momentum is:

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