Two metal slabs of same cross-sectional area have thicknesses $d_1$ and $d_2$,and thermal conductivities $K_1$ and $K_2$ respectively,are connected in series. The free ends of the two slabs are kept at temperatures $T_1$ and $T_2$ $(T_1 > T_2)$. The temperature $T$ of their common junction is
- A$\frac{K_1 T_1 d_2 + K_2 T_2 d_1}{K_1 d_2 + K_2 d_1}$
- B$\frac{K_1 T_1 + K_2 T_2}{K_1 + K_2}$
- C$\frac{K_1 T_1 + K_2 T_2}{T_1 + T_2}$
- D$\frac{K_1 T_1 d_1 + K_2 T_2 d_2}{K_1 d_2 + K_2 d_1}$
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