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(C) Let the intensity of the incident unpolarized light be $I_0$.When unpolarized light passes through the first Nicol prism (polarizer),the intensity

Vedclass · Accepted Answer

$12.5$

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(C) Let the intensity of the incident unpolarized light be $I_0$.When unpolarized light passes through the first Nicol prism (polarizer),the intensity of the transmitted polarized light becomes $I_1 = \frac{I_0}{2}$.According to Malus' Law,when this polarized light passes through the second Nicol prism (analyzer) oriented at an angle $	heta = 60^\circ$ with respect to the first,the transmitted intensity $I_2$ is given by $I_2 = I_1 \cos^2 	heta$.Substituting the values: $I_2 = \frac{I_0}{2} \cos^2(60^\circ) = \frac{I_0}{2} 	imes (\frac{1}{2})^2 = \frac{I_0}{2} 	imes \frac{1}{4} = \frac{I_0}{8}$.The percentage of incident light transmitted is $\frac{I_2}{I_0} 	imes 100 = \frac{1}{8} 	imes 100 = 12.5\%$.

Two Nicols are oriented with their principal planes making an angle of $60^\circ$. The percentage of incident unpolarized light which passes through the system is......$\%$

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