Two numbers are respectively 12 frac{1}{2} % | vedclass

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(A) Let the third number be $100$.The first number is $12 \frac{1}{2} \%$ more than the third number,so it is $100 + 12.5 = 112.5$.The second number i

Vedclass · Accepted Answer

$90$

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(A) Let the third number be $100$.The first number is $12 \frac{1}{2} \%$ more than the third number,so it is $100 + 12.5 = 112.5$.The second number is $25 \%$ more than the third number,so it is $100 + 25 = 125$.We need to find what percentage the first number is of the second number.Required percentage $= \left( \frac{112.5}{125} ight) 	imes 100 \%$.$= 0.9 	imes 100 \% = 90 \%$.

Two numbers are respectively $12 \frac{1}{2} \%$ and $25 \%$ more than a third number. The first number is what percentage of the second number?

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