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(D) Let the two numbers be $3x$ and $5x$.According to the problem,if each number is increased by $10$,the new ratio becomes $5:7$.So,$\frac{3x + 10}{5

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$15, 25$

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(D) Let the two numbers be $3x$ and $5x$.According to the problem,if each number is increased by $10$,the new ratio becomes $5:7$.So,$\frac{3x + 10}{5x + 10} = \frac{5}{7}$.Cross-multiplying,we get $7(3x + 10) = 5(5x + 10)$.$21x + 70 = 25x + 50$.$25x - 21x = 70 - 50$.$4x = 20$.$x = 5$.Therefore,the numbers are $3(5) = 15$ and $5(5) = 25$.

Two numbers are such that the ratio between them is $3:5;$ but if each is increased by $10,$ the ratio between them becomes $5:7.$ The numbers are

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