Two open beakers,one containing a solvent and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The pure solvent has a higher vapour pressure than the solution containing a non-volatile solute. In the sealed container,the solvent molecules ev

Vedclass · Accepted Answer

The volume of the solution increases and the volume of the solvent decreases.

Vedclass · Answer

(C) The pure solvent has a higher vapour pressure than the solution containing a non-volatile solute. In the sealed container,the solvent molecules evaporate from the pure solvent beaker to establish equilibrium. Since the solution has a lower vapour pressure,the solvent vapour condenses into the solution beaker to maintain the equilibrium vapour pressure. Consequently,the volume of the pure solvent decreases while the volume of the solution increases.

Two open beakers,one containing a solvent and the other containing a mixture of that solvent with a non-volatile solute,are together sealed in a container. Over time:

Similar Questions

The vapor pressure of water at a certain temperature is $3000 \ N \ m^{-2}$. When a non-electrolyte solute is added,it decreases by $300 \ N \ m^{-2}$. The molality of the solution is ............. $m$.

The vapor pressure of a liquid mixture of $X$ and $Y$ is given by the equation $P = 160X_x + 50$,where $X_x$ is the mole fraction of $X$. The ratio of the vapor pressures of pure liquids $X$ and $Y$ is:

If the vapour pressure of a solution containing a non-volatile solute is $2\%$ less than the vapour pressure of pure water,find the molality of the solution.

When a solute is added to a solvent having a vapor pressure of $0.80 \ atm$,the vapor pressure decreases to $0.60 \ atm$. The mole fraction of the solute is .........

Vapour pressure of a solution is

Vedclass Test Series

Exam Paper Generator

Online Exam Module