Two packs of 52 cards are shuffled together. | vedclass

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(A) There are $52$ distinct types of cards (suit and denomination combination). Since there are two packs,each of these $52$ types appears twice.To se

Vedclass · Accepted Answer

$^{52}C_{26} \cdot 2^{26}$

Vedclass · Answer

(A) There are $52$ distinct types of cards (suit and denomination combination). Since there are two packs,each of these $52$ types appears twice.To select $26$ cards such that no two cards have the same suit and same denomination,we must first choose $26$ distinct types out of the $52$ available types. This can be done in $^{52}C_{26}$ ways.For each of the $26$ chosen cards,we have $2$ choices (either from the first pack or the second pack).Since there are $26$ such cards,the total number of ways is $^{52}C_{26} 	imes 2^{26}$.

Two packs of $52$ cards are shuffled together. The number of ways in which a man can be dealt $26$ cards so that he does not get two cards of the same suit and same denomination is

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