Two particles of masses $1\,kg$ and $3\,kg$ have position vectors $2\hat{i} + 3\hat{j} + 4\hat{k}$ and $-2\hat{i} + 3\hat{j} - 4\hat{k}$ respectively. The position vector of the centre of mass is:

  • A
    $-\hat{i} - 3\hat{j} - 2\hat{k}$
  • B
    $\hat{i} + 3\hat{j} - 2\hat{k}$
  • C
    $-\hat{i} + 3\hat{j} + 2\hat{k}$
  • D
    $-\hat{i} + 3\hat{j} - 2\hat{k}$

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