Two pipes A and B can fill a cistern in 24 mi | vedclass

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(B) Let the capacity of the cistern be the Least Common Multiple $(LCM)$ of $24, 30,$ and $20$,which is $120$ units.Efficiency of pipe $A = 120 / 24 =

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(B) Let the capacity of the cistern be the Least Common Multiple $(LCM)$ of $24, 30,$ and $20$,which is $120$ units.Efficiency of pipe $A = 120 / 24 = 5$ units/min.Efficiency of pipe $B = 120 / 30 = 4$ units/min.Efficiency of $(A + B - C) = 120 / 20 = 6$ units/min.Here,$C$ is an outlet pipe,so its efficiency is subtracted.$5 + 4 - 	ext{Efficiency of } C = 6$.$9 - 	ext{Efficiency of } C = 6$.Efficiency of $C = 9 - 6 = 3$ units/min.Time taken by $C$ to empty the full cistern $= 	ext{Total capacity} / 	ext{Efficiency of } C = 120 / 3 = 40$ minutes.

Two pipes $A$ and $B$ can fill a cistern in $24$ $minutes$ and $30$ $minutes$,respectively. There is also an outlet $C$. If all the three pipes are opened together,the cistern is full in $20$ $minutes$. How much time (in $minutes$) will be taken by outlet $C$ to empty the full cistern?

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