Two plane mirrors are at right angles to each | vedclass

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(C) When two plane mirrors are placed at an angle of $90^{\circ}$,the number of images formed is given by the formula $n = (360^{\circ} / 	heta) - 1$

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) When two plane mirrors are placed at an angle of $90^{\circ}$,the number of images formed is given by the formula $n = (360^{\circ} / 	heta) - 1$. Substituting $	heta = 90^{\circ}$,we get $n = (360^{\circ} / 90^{\circ}) - 1 = 4 - 1 = 3$ images. Let the man be standing in the first quadrant. The three images are formed at: $1$. Image $I_1$ in the first mirror (lateral inversion occurs). $2$. Image $I_2$ in the second mirror (lateral inversion occurs). $3$. Image $I_3$ which is the image of $I_1$ (or $I_2$) in the other mirror (double lateral inversion occurs). In $I_1$ and $I_2$,the man appears to use his left hand due to single lateral inversion. In $I_3$,the image undergoes two lateral inversions,so the left-right orientation is restored to the original state (he appears to use his right hand). Therefore,in $2$ images,he will be seen using his left hand.

Two plane mirrors are at right angles to each other. $A$ man stands between them and combs his hair with his right hand. In how many images will he be seen using his left hand?

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