Two protons are kept at a separation of 10 n | vedclass

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Question

(D) The nuclear force is a short-range force that acts effectively only within a range of approximately $1 \ fm$ to $3 \ fm$ $(1 \ fm = 10^{-15} \ m)$

Vedclass · Accepted Answer

$F_e \gg F_n$

Vedclass · Answer

(D) The nuclear force is a short-range force that acts effectively only within a range of approximately $1 \ fm$ to $3 \ fm$ $(1 \ fm = 10^{-15} \ m)$.Given the separation between the two protons is $10 \ nm = 10 	imes 10^{-9} \ m = 10^{-8} \ m$.Since $10^{-8} \ m$ is much larger than the range of the nuclear force $(10^{-15} \ m)$,the nuclear force $F_n$ is negligible at this distance.However,the electromagnetic force $F_e$ (Coulomb force) follows an inverse-square law and acts over long distances.Therefore,at a separation of $10 \ nm$,the electromagnetic force is significantly greater than the nuclear force,i.e.,$F_e \gg F_n$.

Two protons are kept at a separation of $10 \ nm$. Let $F_n$ and $F_e$ be the nuclear force and the electromagnetic force between them,respectively.

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