Two pure inductors each of self inductance $L$ are connected in parallel but are well separated from each other. The total inductance is

The equivalent inductance between $A$ and $B$ is equal to

Two coils of self-inductance $L_{1}$ and $L_{2}$ are connected in series. If the mutual inductance of the coils is $M$,the equivalent self-inductance of the combination shown in the figure will be:

Two coils of self-inductances $6 mH$ and $8 mH$ are connected in series and are adjusted for the highest coefficient of coupling. The equivalent self-inductance $L$ for the assembly is approximately: (in $mH$)

An inductor coil of inductance $L$ is cut into two equal parts and both the parts are connected in parallel. The net inductance is

$A$ coil of inductance $L$ is divided into $6$ equal parts. All these parts are connected in parallel. The resultant inductance of this combination is