Two resistances {R_1} and {R_2} are connected | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) When battery ${E_2}$ is short-circuited,the terminals across which ${R_2}$ is connected are joined by a wire of zero resistance.This effectively b

Vedclass · Accepted Answer

${E_1}/{R_1}$

Vedclass · Answer

(A) When battery ${E_2}$ is short-circuited,the terminals across which ${R_2}$ is connected are joined by a wire of zero resistance.This effectively bypasses the resistor ${R_2}$,meaning no current flows through ${R_2}$ because the path of least resistance is the short-circuit wire.Consequently,the circuit simplifies to a single loop containing the battery ${E_1}$ and the resistor ${R_1}$.According to Ohm's law,the current $I$ flowing through the resistor ${R_1}$ is given by $I = {E_1}/{R_1}$.

Two resistances ${R_1}$ and ${R_2}$ are connected as shown in the figure to two batteries of $e.m.f.$ ${E_1}$ and ${E_2}$. If ${E_2}$ is short-circuited,the current through ${R_1}$ is

Similar Questions

In the circuit shown in the figure,the reading of the voltmeter is $V_1$ when only $S_1$ is closed,and the reading of the voltmeter is $V_2$ when only $S_2$ is closed. The reading of the voltmeter is $V_3$ when both $S_1$ and $S_2$ are closed. Then:

$A$ coil of $100 \, W, 220 \, V$ is cut into two equal parts and connected in parallel. How much heat in $J$ is produced in $1 \, sec$?

Consider the circuit shown in the figure.

Two bulbs are in parallel and they together consume $48\, W$ from a battery of $6\, V$. The resistance of each bulb is ............ $\Omega$.

As shown in the figure,a network of resistors is connected to a battery of $24\,V$ with an internal resistance of $3\,\Omega$. The currents through the resistors $R_4$ and $R_5$ are $I_4$ and $I_5$ respectively. The values of $I_4$ and $I_5$ are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module