(A) The orbital speed $V$ of a satellite revolving around a planet of mass $M$ at a distance $r$ is given by the formula $V = \sqrt{\frac{GM}{r}}$.Giv

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(A) The orbital speed $V$ of a satellite revolving around a planet of mass $M$ at a distance $r$ is given by the formula $V = \sqrt{\frac{GM}{r}}$.Given the radii of the orbits are $R_{1} = 3200 \, km$ and $R_{2} = 800 \, km$.The ratio of the speeds is $\frac{V_{1}}{V_{2}} = \frac{\sqrt{\frac{GM}{R_{1}}}}{\sqrt{\frac{GM}{R_{2}}}} = \sqrt{\frac{R_{2}}{R_{1}}}$.Substituting the values: $\frac{V_{1}}{V_{2}} = \sqrt{\frac{800}{3200}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.Comparing this with $\frac{1}{x}$,we get $x = 2$.

Class 11 Physics Gravitation Motion of Satellites in Circular Orbits and Planets in Elliptical Orbits

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Two satellites $S_{1}$ and $S_{2}$ are revolving in circular orbits around a planet with radii $R_{1} = 3200 \, km$ and $R_{2} = 800 \, km$ respectively. The ratio of the speed of satellite $S_{1}$ to the speed of satellite $S_{2}$ in their respective orbits is $\frac{1}{x}$,where $x =$

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$2$
B
$4$
C
$8$
D
$16$

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Gravitation

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Motion of Satellites in Circular Orbits and Planets in Elliptical Orbits

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Two satellites $S_{1}$ and $S_{2}$ are revolving in circular orbits around a planet with radii $R_{1} = 3200 \, km$ and $R_{2} = 800 \, km$ respectively. The ratio of the speed of satellite $S_{1}$ to the speed of satellite $S_{2}$ in their respective orbits is $\frac{1}{x}$,where $x =$

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The time period of a satellite,revolving above earth's surface at a height equal to $R$ will be (Given $g = \pi^2 \ m/s^2$,$R =$ radius of earth).

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