Two short bar magnets have their magnetic mom | vedclass

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Question

(C) The magnetic field due to a short bar magnet at a point on its equatorial line is given by $B = \frac{\mu_0}{4 \pi} \frac{M}{r^3}$.Here,the distan

Vedclass · Accepted Answer

$2.56 	imes 10^{-4} 	ext{ T}$

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(C) The magnetic field due to a short bar magnet at a point on its equatorial line is given by $B = \frac{\mu_0}{4 \pi} \frac{M}{r^3}$.Here,the distance between the centers is $20 	ext{ cm}$,so the distance of the midpoint from each magnet is $r = 10 	ext{ cm} = 0.1 	ext{ m}$.Since the north poles point towards the geographic south,the magnetic fields produced by both magnets at the midpoint will be in the same direction as the Earth's horizontal magnetic field $(B_H)$.Thus,the resultant magnetic field $B_{net} = B_1 + B_2 + B_H$.$B_1 = \frac{10^{-7} 	imes 1.2}{(0.1)^3} = \frac{1.2 	imes 10^{-7}}{10^{-3}} = 1.2 	imes 10^{-4} 	ext{ T}$.$B_2 = \frac{10^{-7} 	imes 1.0}{(0.1)^3} = \frac{1.0 	imes 10^{-7}}{10^{-3}} = 1.0 	imes 10^{-4} 	ext{ T}$.$B_H = 3.6 	imes 10^{-5} = 0.36 	imes 10^{-4} 	ext{ T}$.$B_{net} = (1.2 + 1.0 + 0.36) 	imes 10^{-4} 	ext{ T} = 2.56 	imes 10^{-4} 	ext{ T}$.

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