Two small spheres,each having an equal positi | vedclass

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(A) In the absence of gravity,the only force acting on each sphere is the electrostatic repulsive force exerted by the other sphere.Since the spheres

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$\frac{Q^2}{16 \pi \varepsilon_0 L^2}$

Vedclass · Answer

(A) In the absence of gravity,the only force acting on each sphere is the electrostatic repulsive force exerted by the other sphere.Since the spheres are held in a horizontal position,the distance between the two spheres is $2L$.According to Coulomb's law,the electrostatic force $F$ between the two charges is given by:$F = \frac{1}{4 \pi \varepsilon_0} \frac{Q \cdot Q}{(2L)^2} = \frac{1}{4 \pi \varepsilon_0} \frac{Q^2}{4L^2} = \frac{Q^2}{16 \pi \varepsilon_0 L^2}$.Since the spheres are in equilibrium,the tension $T$ in each string must balance this electrostatic force.Therefore,$T = F = \frac{Q^2}{16 \pi \varepsilon_0 L^2}$.

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