Two sound waves having a phase difference of | vedclass

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Question

(C) The relationship between path difference $(\Delta x)$ and phase difference $(\phi)$ is given by the formula: $\Delta x = \frac{\lambda}{2\pi} 	im

Vedclass · Accepted Answer

$\lambda / 6$

Vedclass · Answer

(C) The relationship between path difference $(\Delta x)$ and phase difference $(\phi)$ is given by the formula: $\Delta x = \frac{\lambda}{2\pi} 	imes \phi$. Given phase difference $\phi = 60^{\circ}$. Convert the phase difference into radians: $\phi = 60^{\circ} 	imes \frac{\pi}{180^{\circ}} = \frac{\pi}{3} 	ext{ radians}$. Substitute the value of $\phi$ into the formula: $\Delta x = \frac{\lambda}{2\pi} 	imes \frac{\pi}{3}$. Simplifying the expression: $\Delta x = \frac{\lambda}{6}$. Therefore,the path difference is $\lambda / 6$.

Two sound waves having a phase difference of $60^{\circ}$ have a path difference of

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