Two sources of light are 0.6 , mm apart and t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Slit separation $d = 0.6 \, mm = 0.6 	imes 10^{-3} \, m$, distance to screen $D = 1.2 \, m$, wavelength $\lambda = 6000 \, \mathring{A} =

Vedclass · Accepted Answer

$5 \pi \, 	ext{radian}$

Vedclass · Answer

(D) Given: Slit separation $d = 0.6 \, mm = 0.6 	imes 10^{-3} \, m$, distance to screen $D = 1.2 \, m$, wavelength $\lambda = 6000 \, \mathring{A} = 6000 	imes 10^{-10} \, m$, and position on screen $y = 3 \, mm = 3 	imes 10^{-3} \, m$.The path difference $\Delta x$ at a point $y$ is given by $\Delta x = \frac{d \cdot y}{D}$.Substituting the values: $\Delta x = \frac{(0.6 	imes 10^{-3} \, m) 	imes (3 	imes 10^{-3} \, m)}{1.2 \, m} = \frac{1.8 	imes 10^{-6}}{1.2} \, m = 1.5 	imes 10^{-6} \, m$.The phase difference $\Delta \phi$ is related to path difference by $\Delta \phi = \frac{2 \pi}{\lambda} \cdot \Delta x$.Substituting the values: $\Delta \phi = \frac{2 \pi}{6000 	imes 10^{-10}} 	imes 1.5 	imes 10^{-6} = \frac{2 \pi 	imes 1.5 	imes 10^{-6}}{6 	imes 10^{-7}} = \frac{3 \pi 	imes 10^{-6}}{6 	imes 10^{-7}} = 0.5 \pi 	imes 10 = 5 \pi \, 	ext{radian}$.

Similar Questions

In Young's double slit experiment,the two slits are $0.6 \; mm$ apart. The interference pattern is observed on a screen at a distance of $80 \; cm$ from the slits. The first dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light is $\dots \; nm$.

In a Young's double slit experiment,the angular width of a fringe formed on a distant screen is $0.1 \ radian$. Find the distance between the two slits in $\mu m$,if the wavelength of light used is $6000 \ \mathring{A}$.

Two slits,$4 \, mm$ apart,are illuminated by light of wavelength $6000 \, \mathring{A}$. What will be the fringe width on a screen placed $2 \, m$ from the slits in $mm$?

In Young's double-slit experiment,when two light waves form the third minimum,the path difference between them is:

In Young's double slit experiment, for the $n^{th}$ dark fringe $(n = 1, 2, 3, \dots)$ the phase difference of the interfering waves in radian will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module