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(D) The total charge on the system is $Q = 80\,\mu C + 40\,\mu C = 120\,\mu C$.When two spheres are connected by a wire,charge flows until they reach

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$32\,\mu C$ from $A$ to $B$

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(D) The total charge on the system is $Q = 80\,\mu C + 40\,\mu C = 120\,\mu C$.When two spheres are connected by a wire,charge flows until they reach the same potential $V$.The potential of a sphere is given by $V = \frac{kQ}{r}$.After connection,the new charges $Q'_A$ and $Q'_B$ are distributed in proportion to their radii: $\frac{Q'_A}{Q'_B} = \frac{r_A}{r_B}$.Using the formula $Q'_A = Q \left( \frac{r_A}{r_A + r_B} ight)$:$Q'_A = 120\,\mu C \left( \frac{4}{4 + 6} ight) = 120 	imes 0.4 = 48\,\mu C$.The charge that flowed from $A$ is $\Delta Q = Q_{initial} - Q_{final} = 80\,\mu C - 48\,\mu C = 32\,\mu C$.Since the charge on $A$ decreased,$32\,\mu C$ of charge flowed from $A$ to $B$.

Two spheres $A$ and $B$ of radius $4\,cm$ and $6\,cm$ are given charges of $80\,\mu C$ and $40\,\mu C$ respectively. If they are connected by a fine wire,the amount of charge flowing from one to the other is

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