Two spherical nuclei have mass numbers 216 an | vedclass

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(A) The relation between the radius $(R)$ of a nucleus and its mass number $(A)$ is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is an empirical

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$3:2$

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(A) The relation between the radius $(R)$ of a nucleus and its mass number $(A)$ is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is an empirical constant.Given the mass numbers $A_1 = 216$ and $A_2 = 64$,we can find the ratio of their radii as follows:$\frac{R_1}{R_2} = \frac{R_0 A_1^{1/3}}{R_0 A_2^{1/3}} = \left( \frac{A_1}{A_2} \right)^{1/3}$Substituting the given values:$\frac{R_1}{R_2} = \left( \frac{216}{64} \right)^{1/3}$Since $216 = 6^3$ and $64 = 4^3$:$\frac{R_1}{R_2} = \left( \frac{6^3}{4^3} \right)^{1/3} = \frac{6}{4} = \frac{3}{2}$Thus,the ratio $\frac{R_1}{R_2}$ is $3:2$.

Two spherical nuclei have mass numbers $216$ and $64$ with their radii $R_1$ and $R_2$ respectively. The ratio,$\frac{R_1}{R_2}$ is equal to

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