Two stations P and Q are 110 ; km apart on a | vedclass

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(B) The train starting from $P$ travels for $1 \; hour$ (from $7 \; am$ to $8 \; am$) at a speed of $20 \; km/h$. Distance covered by the first train

Vedclass · Accepted Answer

$10 \; am$

Vedclass · Answer

(B) The train starting from $P$ travels for $1 \; hour$ (from $7 \; am$ to $8 \; am$) at a speed of $20 \; km/h$. Distance covered by the first train by $8 \; am = 20 \; km/h 	imes 1 \; h = 20 \; km$. Remaining distance between $P$ and $Q$ at $8 \; am = 110 \; km - 20 \; km = 90 \; km$. Since the trains are moving towards each other,their relative speed $= 20 \; km/h + 25 \; km/h = 45 \; km/h$. Time taken to meet after $8 \; am = \frac{	ext{Remaining Distance}}{	ext{Relative Speed}} = \frac{90 \; km}{45 \; km/h} = 2 \; hours$. Therefore,the trains will meet at $8 \; am + 2 \; hours = 10 \; am$.

Two stations $P$ and $Q$ are $110 \; km$ apart on a straight line. One train starts from $P$ at $7 \; am$ and travels towards $Q$ at $20 \; km/h$ speed. Another train starts from $Q$ at $8 \; am$ and travels towards $P$ at a speed of $25 \; km/h$. At what time will they meet?

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