Two stretched strings A and B when vibrated t | vedclass

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(C) The beat frequency is given by $|n_A - n_B| = 4 \ Hz$.When the tension in string $A$ is increased,its frequency $n_A$ increases because $n \propto

Vedclass · Accepted Answer

$484$

Vedclass · Answer

(C) The beat frequency is given by $|n_A - n_B| = 4 \ Hz$.When the tension in string $A$ is increased,its frequency $n_A$ increases because $n \propto \sqrt{T}$.Since the number of beats increases from $4$ to $7$ upon increasing $n_A$,it implies that $n_A$ must be greater than $n_B$ (i.e.,$n_A - n_B = 4$).If $n_A$ were less than $n_B$,increasing $n_A$ would decrease the beat frequency towards zero before increasing it again,but the problem implies a direct increase.Therefore,$n_A = n_B + 4$.Given $n_B = 480 \ Hz$,we have $n_A = 480 + 4 = 484 \ Hz$.

Two stretched strings $A$ and $B$ when vibrated together produce $4$ beats per second. If the tension applied to the string $A$ is increased,the number of beats produced per second increases to $7$. If the frequency of string $B$ is $480 \ Hz$ initially,what is the frequency of string $A$ (in $Hz$)?

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