Two substances A and B of equal mass m are he | vedclass

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(C) From the given heating curve,the heat absorbed during fusion is given by $H = P 	imes t$,where $P$ is the power (rate of heating) and $t$ is the

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$\frac{8}{5}$

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(C) From the given heating curve,the heat absorbed during fusion is given by $H = P 	imes t$,where $P$ is the power (rate of heating) and $t$ is the time taken for the phase change (fusion).For substance $A$:The fusion process occurs at a constant temperature of $60^\circ C$. The time interval for this phase change is from $t = 2 \, min$ to $t = 6 \, min$.Time taken for fusion,$t_A = 6 - 2 = 4 \, min = 4 	imes 60 \, s = 240 \, s$.Heat absorbed by $A$,$H_A = P 	imes t_A = 6 \, cal \, s^{-1} 	imes 240 \, s = 1440 \, cal$.For substance $B$:The fusion process occurs at a constant temperature of $20^\circ C$. The time interval for this phase change is from $t = 4 \, min$ to $t = 6.5 \, min$.Time taken for fusion,$t_B = 6.5 - 4 = 2.5 \, min = 2.5 	imes 60 \, s = 150 \, s$.Heat absorbed by $B$,$H_B = P 	imes t_B = 6 \, cal \, s^{-1} 	imes 150 \, s = 900 \, cal$.Ratio of heat absorbed:$\frac{H_A}{H_B} = \frac{1440}{900} = \frac{144}{90} = \frac{8}{5}$.

Two substances $A$ and $B$ of equal mass $m$ are heated at a uniform rate of $6 \, cal \, s^{-1}$ under similar conditions. $A$ graph between temperature and time is shown in the figure. The ratio of heat absorbed $H_A/H_B$ by them for complete fusion is

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