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(A) The heat supplied at a constant rate is given by $\Delta H = mC \Delta 	heta$. Since the rate of heat supply $\frac{dH}{dt}$ is constant, we can

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Specific heat of $A$ is greater than that of $B$

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(A) The heat supplied at a constant rate is given by $\Delta H = mC \Delta 	heta$. Since the rate of heat supply $\frac{dH}{dt}$ is constant, we can write: $\frac{dH}{dt} = mC \frac{d	heta}{dt}$. This implies $\frac{d	heta}{dt} = \frac{1}{mC} \left( \frac{dH}{dt} ight)$. Since $m$ and $\frac{dH}{dt}$ are constant, the slope of the $	heta-t$ graph is inversely proportional to the specific heat $C$ (i.e.,$	ext{slope} \propto \frac{1}{C}$). From the figure, the slope of line $B$ is greater than the slope of line $A$ (i.e.,$	ext{slope}_B > 	ext{slope}_A$). Therefore, $C_B < C_A$, which means the specific heat of $A$ is greater than that of $B$.

Two substances $A$ and $B$ of the same mass are heated at a constant rate. The variation of temperature $\theta$ of the substances with time $t$ is shown in the figure. Choose the correct statement.

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