Two taps can fill a tank in 20 min and 30 min | vedclass

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(B) Let the first tap be closed after $x$ minutes.The rate of the first tap is $1/20$ tank per minute,and the rate of the second tap is $1/30$ tank pe

Vedclass · Accepted Answer

$8$

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(B) Let the first tap be closed after $x$ minutes.The rate of the first tap is $1/20$ tank per minute,and the rate of the second tap is $1/30$ tank per minute.The first tap worked for $x$ minutes,and the second tap worked for the entire $18$ minutes.According to the problem,the total work done is equal to filling one full tank:$\frac{x}{20} + \frac{18}{30} = 1$Simplify the equation:$\frac{x}{20} + \frac{3}{5} = 1$Subtract $3/5$ from both sides:$\frac{x}{20} = 1 - \frac{3}{5}$$\frac{x}{20} = \frac{2}{5}$Solve for $x$:$x = \frac{2}{5} 	imes 20$$x = 8$ minutes.Thus,the first tap was closed after $8$ minutes.

Two taps can fill a tank in $20$ $min$ and $30$ $min$ respectively. When the tank was empty,both the taps were opened,and after some time,the first tap was closed. It took $18$ $min$ in total to fill the tank. After how much time (in $minutes$) from the beginning was the first tap closed?

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