Two thin lenses of focal lengths f_1 and f_2 | vedclass

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(D) The equivalent focal length $f$ of two thin lenses in contact is given by the formula: $\frac{1}{f} = \frac{1}{f_1} + \frac{1}{f_2}$.Since the pow

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$\frac{f_1+f_2}{f_1 f_2}$

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(D) The equivalent focal length $f$ of two thin lenses in contact is given by the formula: $\frac{1}{f} = \frac{1}{f_1} + \frac{1}{f_2}$.Since the power $P$ of a lens is defined as $P = \frac{1}{f}$,the power of the combination is $P = P_1 + P_2 = \frac{1}{f_1} + \frac{1}{f_2}$.Simplifying this expression,we get $P = \frac{f_1 + f_2}{f_1 f_2}$.

Two thin lenses of focal lengths $f_1$ and $f_2$ are in contact and coaxial. The power of the combination is

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