Two trains,each of length 125 , m,are running | vedclass

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(B) The total distance covered by the two trains to cross each other is the sum of their lengths: $D = 125 \, m + 125 \, m = 250 \, m$.The time taken

Vedclass · Accepted Answer

$85$

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(B) The total distance covered by the two trains to cross each other is the sum of their lengths: $D = 125 \, m + 125 \, m = 250 \, m$.The time taken to cross is $t = 6 \, s$.The relative speed of the trains moving in opposite directions is the sum of their individual speeds: $V_{rel} = V_1 + V_2$.Given $V_1 = 65 \, km/h$. Let $V_2 = x \, km/h$.Converting relative speed to $m/s$: $V_{rel} = (65 + x) 	imes \frac{5}{18} \, m/s$.Using the formula $Distance = Speed 	imes Time$:$250 = (65 + x) 	imes \frac{5}{18} 	imes 6$$250 = (65 + x) 	imes \frac{5}{3}$$65 + x = 250 	imes \frac{3}{5}$$65 + x = 50 	imes 3 = 150$$x = 150 - 65 = 85 \, km/h$.Therefore,the speed of the other train is $85 \, km/h$.

Two trains,each of length $125 \, m$,are running on parallel tracks in opposite directions. One train is running at a speed of $65 \, km/h$ and they cross each other in $6 \, s$. The speed of the other train is (in $km/h$):

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