Two transparent media having refractive indic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Refractive index of rarer medium $\mu_1 = 1.0$,refractive index of denser medium $\mu_2 = 1.5$. Radius of curvature $R = +30\,cm$ (as the c

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(A) Given: Refractive index of rarer medium $\mu_1 = 1.0$,refractive index of denser medium $\mu_2 = 1.5$. Radius of curvature $R = +30\,cm$ (as the centre of curvature is in the direction of light propagation). Object distance $u = -15\,cm$ (measured against the direction of light).Using the formula for refraction at a spherical surface:$\frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R}$Substituting the values:$\frac{1.5}{v} - \frac{1.0}{-15} = \frac{1.5 - 1.0}{30}$$\frac{1.5}{v} + \frac{1}{15} = \frac{0.5}{30}$$\frac{1.5}{v} + \frac{1}{15} = \frac{1}{60}$$\frac{1.5}{v} = \frac{1}{60} - \frac{1}{15}$$\frac{1.5}{v} = \frac{1 - 4}{60} = \frac{-3}{60} = -\frac{1}{20}$$v = 1.5 	imes (-20) = -30\,cm$.The negative sign indicates that the image is formed on the same side as the object at a distance of $30\,cm$ from the pole.

Similar Questions

$A$ laser beam falls on a crystal ball of radius $R$ as shown in the figure. What is its refractive index?

As shown in the figure,an air bubble is located at a distance of $3 \, cm$ from a spherical surface of a glass $(\mu = 1.5)$ with a diameter of $10 \, cm$. If the surface is concave,at what distance from the surface will the bubble appear? (in $cm$)

$A$ point source of light at the surface of a sphere causes a parallel beam of light to emerge from the opposite surface of the sphere. The refractive index of the material of the sphere is

Vedclass Test Series

Exam Paper Generator

Online Exam Module