Two tuning forks,$A$ and $B$,produce $4$ beats per second when sounded together. The frequency of $A$ is $320 \ Hz$. When some wax is added to $B$ and it is sounded with $A$,$4$ beats per second are again heard. The frequency of $B$ is .... $Hz$.

$A$ prong of a vibrating tuning fork is in contact with the water surface. It produces concentric circular waves on the surface of the water. The distance between five consecutive crests is $0.8 \ m$ and the velocity of the wave on the water surface is $56 \ m/s$. The frequency of the tuning fork is: (in $Hz$)

Two wires are producing fundamental notes of the same frequency. Change in which of the following factors of one wire will not produce beats between them?

When a vibrating tuning fork moves towards a wall,why do we hear sound beats?

Two tuning forks $A$ and $B$ sounded together give $6$ beats per second. With an air resonance tube closed at one end,the two forks give resonance when the two air columns are $24 \, cm$ and $25 \, cm$ respectively. Calculate the frequencies of the forks.

The wavelengths of two sound notes in air are $\frac{40}{195} \,m$ and $\frac{40}{193} \,m$. Each note produces $9$ beats per second separately with a third note of fixed frequency. The velocity of sound in air in $m/s$ is