Two tuning forks have frequencies $380 \ Hz$ and $384 \ Hz$ respectively. When they are sounded together,they produce $4$ beats per second. After hearing the maximum sound,how long will it take to hear the minimum sound in seconds?

Two vibrating tuning forks produce progressive waves given by $y_1 = 4 \sin(500 \pi t)$ and $y_2 = 2 \sin(506 \pi t)$. These tuning forks are held near the ear of a person. The person will hear

$A$ vibrating tuning fork of frequency $n$ is placed near the open end of a long cylindrical tube. The tube has a side opening and is fitted with a movable reflecting piston. As the piston is moved through $8.75 \, cm$,the intensity of sound changes from a maximum to a minimum. If the speed of sound is $350 \, m/s$,then $n$ is .... $Hz$.

The wavelengths of two waves are $50 \ cm$ and $51 \ cm$ respectively. If the temperature of the room is $20^{\circ}C$,what will be the number of beats produced per second by these waves,given that the speed of sound at $0^{\circ}C$ is $332 \ m/s$?

Two sound sources,when sounded simultaneously,produce four beats in $0.25 \ s$. The difference in their frequencies must be: (in $Hz$)

Two sources of sound placed close to each other are emitting progressive waves given by $y_1 = 4 \sin(600\pi t)$ and $y_2 = 5 \sin(608\pi t)$. An observer located near these two sources of sound will hear: