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(A) From the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$ is the number of moles.Since the vessels have the same size $(V_A = V_B)$ and are a

Vedclass · Accepted Answer

$16$

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(A) From the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$ is the number of moles.Since the vessels have the same size $(V_A = V_B)$ and are at the same temperature $(T_A = T_B)$,the pressure $P$ is directly proportional to the number of moles $n$ $(P \propto n)$.Therefore,$\frac{P_A}{P_B} = \frac{n_A}{n_B}$.The molar mass of hydrogen $(H_2)$ is $M_A = 2 \ g/mol$,and the molar mass of oxygen $(O_2)$ is $M_B = 32 \ g/mol$.The number of moles in vessel $A$ is $n_A = \frac{1 \ g}{2 \ g/mol} = 0.5 \ mol$.The number of moles in vessel $B$ is $n_B = \frac{1 \ g}{32 \ g/mol} = \frac{1}{32} \ mol$.Thus,$\frac{P_A}{P_B} = \frac{0.5}{1/32} = 0.5 	imes 32 = 16$.

Two vessels $A$ and $B$ are of the same size and are at the same temperature. Vessel $A$ contains $1 \ g$ of hydrogen and vessel $B$ contains $1 \ g$ of oxygen. If $P_{A}$ and $P_{B}$ are the pressures of the gases in $A$ and $B$ respectively,then the ratio $\frac{P_{A}}{P_{B}}$ is:

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