Two waves represented by y_1 = 10 sin(200pi t | vedclass

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(C) The equations of the two waves are $y_1 = A_1 \sin(\omega t)$ and $y_2 = A_2 \sin(\omega t + \phi)$.Here,$A_1 = 10$,$A_2 = 20$,and the phase diffe

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$10\sqrt{5}$

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(C) The equations of the two waves are $y_1 = A_1 \sin(\omega t)$ and $y_2 = A_2 \sin(\omega t + \phi)$.Here,$A_1 = 10$,$A_2 = 20$,and the phase difference $\phi = \pi/2$.The amplitude of the resultant wave $R$ is given by the formula $R = \sqrt{A_1^2 + A_2^2 + 2A_1A_2 \cos \phi}$.Substituting the values: $R = \sqrt{10^2 + 20^2 + 2(10)(20) \cos(\pi/2)}$.Since $\cos(\pi/2) = 0$,the expression simplifies to $R = \sqrt{100 + 400 + 0} = \sqrt{500}$.Therefore,$R = 10\sqrt{5}$.

Two waves represented by $y_1 = 10 \sin(200\pi t)$ and $y_2 = 20 \sin(200\pi t + \pi/2)$ are superimposed at a point. The amplitude of the resultant wave is

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