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(D) Given: Power $P = 1 	ext{ kW} = 1000 	ext{ W}$,Voltage $V = 100 	ext{ V}$,Distance $a = 2 	ext{ mm} = 2 	imes 10^{-3} 	ext{ m}$.First,calcul

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$10^{-2} 	ext{ N}$

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(D) Given: Power $P = 1 	ext{ kW} = 1000 	ext{ W}$,Voltage $V = 100 	ext{ V}$,Distance $a = 2 	ext{ mm} = 2 	imes 10^{-3} 	ext{ m}$.First,calculate the current $I$ flowing through the wires using $P = VI$:$I = \frac{P}{V} = \frac{1000}{100} = 10 	ext{ A}$.The force per unit length $f$ between two parallel wires carrying current $I$ is given by the formula:$f = \frac{\mu_0 I^2}{2\pi a}$.Substituting the values:$f = \frac{(4\pi 	imes 10^{-7}) 	imes (10)^2}{2\pi 	imes (2 	imes 10^{-3})}$.$f = \frac{4\pi 	imes 10^{-7} 	imes 100}{4\pi 	imes 10^{-3}}$.$f = 10^{-7} 	imes 10^2 	imes 10^3 = 10^{-2} 	ext{ N/m}$.Thus,the force per metre is $10^{-2} 	ext{ N}$.

Two wires $2 \text{ mm}$ apart supply current to a $100 \text{ V}$,$1 \text{ kW}$ heater. The force per metre between the wires is (Given $\mu_0 = 4\pi \times 10^{-7} \text{ T m/A}$)

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