Two wooden blocks are moving on a smooth hori | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $a$ be the acceleration of the system. The force $P$ is applied to the block of mass $M$. The total mass of the system is $(M + m)$.According

Vedclass · Accepted Answer

$(M + m)g 	an \beta$

Vedclass · Answer

(A) Let $a$ be the acceleration of the system. The force $P$ is applied to the block of mass $M$. The total mass of the system is $(M + m)$.According to Newton's second law,$P = (M + m)a$,so $a = \frac{P}{M + m}$.For the block of mass $m$ to remain stationary with respect to $M$,it must move with the same acceleration $a$ in the horizontal direction.The forces acting on mass $m$ are:$1$. Gravitational force $mg$ acting downwards.$2$. Normal reaction $N$ from the surface of $M$,acting perpendicular to the inclined surface.Resolving the forces on $m$ in the horizontal and vertical directions:Horizontal: $N \sin \beta = ma$Vertical: $N \cos \beta = mg$Dividing the two equations: $\frac{N \sin \beta}{N \cos \beta} = \frac{ma}{mg} \implies 	an \beta = \frac{a}{g} \implies a = g 	an \beta$.Substituting $a$ into the force equation: $P = (M + m)g 	an \beta$.

Two wooden blocks are moving on a smooth horizontal surface such that the mass $m$ remains stationary with respect to the block of mass $M$ as shown in the figure. The magnitude of force $P$ is

Similar Questions

If $1, \log_9(3^{1-x} + 2), \log_3(4 \cdot 3^x - 1)$ are in $A.P.$,then $x$ equals

If the mean of the data $7, 8, 9, 7, 8, 7, \lambda, 8$ is $8$,then the variance of this data is

Two long parallel wires are at a distance $2d$ apart. They carry steady equal currents flowing out of the plane of the paper,as shown. The variation of the magnetic field $B$ along the line $XX'$ is given by

The mid-point of a chord of the ellipse $x^2+4y^2-2x+20y=0$ is $(2, -4)$. The equation of the chord is

Vedclass Test Series

Exam Paper Generator

Online Exam Module