The unknown compound (A) is: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction involves the base-catalyzed tautomerization of an $\alpha$-hydroxy ketone. In the presence of traces of base,the hydroxyl proton is r

Vedclass · Accepted Answer

$2-$hydroxycyclohexanone with the carbonyl group at the labeled carbon

Vedclass · Answer

(B) The reaction involves the base-catalyzed tautomerization of an $\alpha$-hydroxy ketone. In the presence of traces of base,the hydroxyl proton is removed to form an enolate intermediate. The enolate can be protonated at different positions,leading to the equilibration of the $\alpha$-hydroxy ketone. Specifically,the labeled carbon $(C^{14})$ which is initially attached to the hydroxyl group becomes the carbonyl carbon in the tautomerized product $(A)$. Thus,the product $(A)$ is $2$-hydroxycyclohexanone where the carbonyl group is at the labeled carbon.

The unknown compound $(A)$ is:

Similar Questions

Identify the conformer of $2$-methylpentane.

What is isomerism? Which are the types of isomerism?

Choose the correct relation between $l_1$ and $l_2$ for the given allene derivative (butatriene system):

Identify the correct orders among the following:

How many stereoisomers does this molecule have?
$CH_3CH=CHCH_2CH(Br)CH_3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module