Unpolarised light is incident from air on a plane surface of a material of refractive index $\mu$. At a particular angle of incidence $i$,it is found that the reflected and refracted rays are perpendicular to each other. Which of the following options is correct for this situation?
- AReflected light is polarised with its electric vector parallel to the plane of incidence
- BReflected light is polarised with its electric vector perpendicular to the plane of incidence
- C$i = \tan^{-1}(1/\mu)$
- D$i = \sin^{-1}(1/\mu)$
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At what angle should an unpolarised beam be incident on a crystal of $\mu = \sqrt{3}$,so that the reflected beam is polarised (in $^{\circ}$)?
Easy
View SolutionGiven below are two statements:
Statement $I$: If the Brewster's angle for the light propagating from air to glass is $\theta_B$,then Brewster's angle for the light propagating from glass to air is $\frac{\pi}{2} - \theta_B$.
Statement $II$: The Brewster's angle for the light propagating from glass to air is $\tan^{-1}(\mu_g)$ where $\mu_g$ is the refractive index of glass.
In the light of the above statements,choose the correct answer from the options given below:
Statement $I$: If the Brewster's angle for the light propagating from air to glass is $\theta_B$,then Brewster's angle for the light propagating from glass to air is $\frac{\pi}{2} - \theta_B$.
Statement $II$: The Brewster's angle for the light propagating from glass to air is $\tan^{-1}(\mu_g)$ where $\mu_g$ is the refractive index of glass.
In the light of the above statements,choose the correct answer from the options given below:
$A$ ray of unpolarised light is incident on a glass surface of refractive index $1.73$ at the polarizing angle. The angle of refraction will be. [Take $\tan 60^{\circ} = 1.73$] (in $^{\circ}$)
Choose the $CORRECT$ statement from the following. Brewster's angle for a transparent medium is
$A$ camera equipped with a polariser is placed on a mountain to record only the reflected image of the sun from the surface of a sea,as shown in the figure. If the sun rises at $6.00 \, AM$ and sets at $6.00 \, PM$ during the summer,then at what time in the afternoon will the recorded image have the lowest intensity? Assume there are no clouds and the intensity of the sun at the sea surface is constant throughout the day. (Refractive index of water $= 1.33$)
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