Upon fully dissolving 2.0 g of a metal in su | vedclass

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(B) The principle of equivalence states that the number of equivalents of the metal equals the number of equivalents of the metal sulphate formed.Let

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$20.0$

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(B) The principle of equivalence states that the number of equivalents of the metal equals the number of equivalents of the metal sulphate formed.Let the equivalent weight of the metal be $x$.The equivalent weight of the sulphate ion $(SO_4^{2-})$ is $\frac{96}{2} = 48$.Thus,the equivalent weight of the metal sulphate is $(x + 48)$.Using the formula: $\frac{	ext{Mass of metal}}{	ext{Eq. wt. of metal}} = \frac{	ext{Mass of metal sulphate}}{	ext{Eq. wt. of metal sulphate}}$$\frac{2.0}{x} = \frac{6.8}{x + 48}$$2.0(x + 48) = 6.8x$$2x + 96 = 6.8x$$4.8x = 96$$x = \frac{96}{4.8} = 20.0 \ g$.

Upon fully dissolving $2.0 \ g$ of a metal in sulphuric acid,$6.8 \ g$ of the metal sulphate is formed. The equivalent weight of the metal is $...... \ g$.

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